{"id":812,"date":"2019-08-27T21:24:59","date_gmt":"2019-08-27T21:24:59","guid":{"rendered":"https:\/\/pressbooks.library.ryerson.ca\/controlsystems\/?post_type=chapter&#038;p=812"},"modified":"2021-01-12T20:00:41","modified_gmt":"2021-01-12T20:00:41","slug":"7-3-examples","status":"publish","type":"chapter","link":"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/chapter\/7-3-examples\/","title":{"raw":"7.3 Examples","rendered":"7.3 Examples"},"content":{"raw":"<strong>7.3.1 Example<\/strong>\r\n\r\nConsider a certain closed loop control system as shown:\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_5-300x123.png\" alt=\"\" width=\"300\" height=\"123\" class=\"aligncenter size-medium wp-image-815 aligncenter\" \/><\/p>\r\nFind the closed loop system transfer function and determine the system parameters [latex]K_{dc}, \\zeta,\\omega_{o}[\/latex]. Next, determine the following step response specifications: Percent Overshoot (PO), Settling Time ([latex]T_{settle(\\pm 2\\%)}[\/latex]), Rise Time ([latex]T_{rise(10\\% - 90\\%)}[\/latex]), period of oscillations ([latex]T_{period}[\/latex]), and frequency of damped oscillations ([latex]\\omega_{d}[\/latex]), the System Type, Error Constants and Steady State Errors for the step, ramp and parabolic inputs.\r\n\r\n&nbsp;\r\n\r\n<strong>7.3.2 Example<\/strong>\r\n\r\nConsider a certain closed loop system operating under Proportional Control as shown, and find the gain value such that the system is stable and PO is approximately 20%. What is the Settling Time? Can it be improved?\r\n\r\n&nbsp;\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_6-300x80.png\" alt=\"\" width=\"506\" height=\"135\" class=\"wp-image-817 aligncenter\" \/><\/p>\r\n<strong>7.3.3 Example<\/strong>\r\n\r\nConsider a pole-zero map of a certain closed loop system, as shown. Estimate the settling time, [latex]T_{settle(2\\%)}[\/latex], of the system step response and the closed loop system damping ratio.\r\n\r\n&nbsp;\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_7-300x232.png\" alt=\"\" width=\"472\" height=\"365\" class=\" wp-image-818 aligncenter\" \/><\/p>\r\n&nbsp;\r\n\r\n<strong>7.3.4 Example<\/strong>\r\n\r\nConsider an unknown closed loop system with a normalized (i.e. scaled so that the reference input is equal to ) step response as shown. Find an appropriate model for the closed loop transfer function.\r\n\r\n&nbsp;\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_8-300x225.png\" alt=\"\" width=\"547\" height=\"410\" class=\"wp-image-819 aligncenter\" \/><\/p>\r\n&nbsp;\r\n\r\n<strong>7.3.5 Example<\/strong>\r\n\r\nConsider a response of a closed loop control system from Example 5.3.10. Read off transient and steady state step response specifications ([latex]PO, T_{rise(10\\% - 90\\%)} , T_{settle \\pm 2\\%}, T_{period}, [\/latex] and [latex]e_{ss\\%}[\/latex]). Based on the information, build an appropriate second order model for the system with such step response as shown.\r\n\r\n&nbsp;\r\n\r\n<strong>7.3.6 Example<\/strong>\r\n\r\nConsider a certain closed loop control system described by the following transfer function:\r\n\r\n[latex]G_{cl}(s) = \\frac{Y(s)}{R(s)} = \\frac{22.5}{s^{2} + s + 25}[\/latex]\r\n\r\nFind the closed loop system damping ratio, frequency of natural oscillation and closed loop DC gain.\r\n\r\nNext, estimate the following transient response specifications: percent overshoot (PO), settling time ([latex]T_{settle(\\pm 2\\%)}[\/latex]), period ( [latex]T_{period}[\/latex]), and frequency of damped oscillations (), as well as the following steady state specifications of this closed loop system: System Type as well as Position Constant, steady state error to a step input (in %), Velocity Constant, steady state error to a ramp input, Acceleration Constant and steady state error to a parabolic input.\r\n\r\nHow many cycles of oscillations will be visible in the system response? Justify your answer.\r\n\r\n&nbsp;\r\n\r\n<strong>7.3.7 Example<\/strong>\r\n\r\nConsider a response of a certain closed loop control system to a unit reference signal, shown in the figure below.\r\n\r\n&nbsp;\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_9-300x240.png\" alt=\"\" width=\"530\" height=\"424\" class=\" wp-image-821 aligncenter\" \/><\/p>\r\n&nbsp;\r\n\r\nRead off appropriate values and\/or calculate transient specifications (PO, settling time ([latex]T_{settle(\\pm 2\\%)}[\/latex]), period ( [latex]T_{period}[\/latex]) for this step response. Identify the System Type, Steady State Errors to unit step, ramp and parabolic inputs, as well as the corresponding Position, Velocity and Acceleration Constants. Based on the information read off in Part 1, create a second order model for the closed loop system with the response shown. Find the following system parameters: [latex]\\zeta, \\omega_{n}, K_{dc}[\/latex] , as well as the complete model transfer function [latex]G_{model}(s)[\/latex] .\r\n\r\n&nbsp;\r\n\r\n<strong>7.3.8 Example<\/strong>\r\n\r\nConsider a certain closed loop control system described by the following transfer function:\r\n\r\n[latex]G_{cl}(s) = \\frac{Y(s)}{R(s)} = \\frac{80}{s^{2} + 5s + 100}[\/latex]\r\n\r\nFind the following model parameters: [latex]\\zeta, \\omega_{n}, K_{dc}[\/latex]. Estimate transient response specifications (PO, settling time ([latex]T_{settle(\\pm 2\\%)}[\/latex]), period ( [latex]T_{period}[\/latex]) and steady state specifications of this closed loop system (System Type, [latex]K_{pos}, e_{ss(step)\\%}, K_{v}, e_{ss(ramp)}, K_{a}, e_{ss(parab)}[\/latex] ).\r\n\r\n&nbsp;\r\n\r\n<strong>7.3.9 Example<\/strong>\r\n\r\nConsider four separate second order systems, with the locations of their pole pairs shown. Answer the following questions and give brief justification to your answer.\r\n\r\n<strong>Q:<\/strong> Which of the four systems exhibits the largest percent overshoot (PO) in its step response?\r\n\r\n<strong>Q:<\/strong> Which of the four systems is unstable?\r\n\r\n<strong>Q:<\/strong> Which of the four systems exhibits the shortest settling time in its step response?\r\n\r\n<strong>Q:<\/strong> Which of the four systems has the highest frequency of oscillations in its step response?\r\n\r\n<strong>Q:<\/strong> Which of the four systems exhibits the longest settling time in its step response?\r\n\r\n<strong>Q:<\/strong> Which of the four systems exhibits the smallest percent overshoot (PO) in its step response?\r\n\r\n<strong>Q:<\/strong> Which of the four systems has the smallest steady state error?\r\n\r\n<strong>Q:<\/strong> What is the System Type?\r\n\r\n&nbsp;\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_10-300x239.png\" alt=\"\" width=\"527\" height=\"421\" class=\" wp-image-822 aligncenter\" \/><\/p>\r\n&nbsp;\r\n\r\n<strong>7.3.10 Example<\/strong>\r\n\r\nConsider closed loop responses of two different control systems (System A and System B), as shown. Match them to their appropriate pole locations also shown, briefly explain why.\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_11-300x243.png\" alt=\"\" width=\"432\" height=\"350\" class=\"alignnone wp-image-823\" \/><\/p>\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_12-300x217.png\" alt=\"\" width=\"487\" height=\"352\" class=\"alignnone wp-image-824\" \/><\/p>\r\n&nbsp;\r\n\r\n<strong>7.3.11 Example<\/strong>\r\n\r\nConsider a normalized step response of a certain LTI system, as shown. The reference is assumed to be a unit step.\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_13-300x225.png\" alt=\"\" width=\"605\" height=\"455\" class=\"wp-image-826 aligncenter\" \/><\/p>\r\nDetermine the Percent Overshoot (in %), Steady State Error (in %) and the Settling Time (within \u00b12% of the final value) for this response. Next, assume that this system can be modelled by a standard 2nd order model and calculate the appropriate parameters.\r\n\r\n&nbsp;\r\n\r\n<strong>7.3.12 Example<\/strong>\r\n\r\nConsider a response of a certain closed loop control system to a unit reference signal, shown in the figure below.\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_14-300x257.png\" alt=\"\" width=\"594\" height=\"509\" class=\"wp-image-827 aligncenter\" \/><\/p>\r\nRead off appropriate values and\/or calculate transient specifications (PO, settling time ([latex]T_{settle(\\pm 2\\%)}[\/latex]), period ([latex]T_{period}[\/latex]) for this step response. Based on the information read off in Part 1, create a second order model for the closed loop system with the response shown. Find the following system parameters: [latex]\\zeta, \\omega_{n}, K_{dc}[\/latex], as well as the complete model transfer function [latex]G_{model}(s)[\/latex]. Identify the System Type, Steady State Errors to unit step, ramp and parabolic inputs, as well as the corresponding Position, Velocity and Acceleration Constants.\r\n\r\n&nbsp;\r\n\r\n<strong>7.3.13 Example<\/strong>\r\n\r\nConsider a step response to a unit reference input of a control system as shown. Estimate the following specs: Percent Overshoot, Settling Time the Steady State Error. What are your estimates of the closed loop damping ratio [latex]\\zeta[\/latex], the frequency of natural oscillations [latex]\\omega_{n}[\/latex], and the DC gain?\r\n\r\n&nbsp;\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_15-300x220.png\" alt=\"\" width=\"588\" height=\"431\" class=\"wp-image-828 aligncenter\" \/><\/p>\r\n&nbsp;\r\n\r\n<strong>7.3.14 Example<\/strong>\r\n\r\nA step response of a certain control system is supposed to exhibit no more than 5% overshoot and to settle (use the 2% definition of the settling time) within (2) seconds. Show a shaded area in the S-Plane where the dominant closed loop poles of the system should be located so that both conditions are met.\r\n\r\n&nbsp;\r\n\r\n<strong>7.3.15 Example<\/strong>\r\n\r\nConsider the closed loop control system as shown here.\r\n\r\n&nbsp;\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_16-300x102.png\" alt=\"\" width=\"460\" height=\"156\" class=\" wp-image-829 aligncenter\" \/><\/p>\r\nFor [latex]\\tau = = 2 [\/latex] seconds, the desired closed loop ratio is to be [latex]\\zeta = \\frac{1}{\\sqrt{2}}[\/latex]. Find the corresponding Controller gain K and the resulting settling time of the closed loop step response. Next, assume that the desired closed loop ratio is still to be [latex]\\zeta = \\frac{1}{\\sqrt{2}}[\/latex]. but we would like to shorten the settling time to [latex]T_{settle \\pm 2\\%} =\u00a0 2 [\/latex] seconds. If the time constant is variable, what value would it have to be? For that case, find the corresponding Controller gain K.\r\n\r\nThe closed loop system characteristic equation Q(s) is a quadratic, resulting in TWO closed loop poles:\r\n\r\n&nbsp;\r\n\r\n[latex]Q(s) = 0[\/latex]\u00a0 \u00a0 \u00a0[latex]s^{2} + \\frac{1}{\\tau}s + \\frac{K}{\\tau} = 0 [\/latex]\r\n\r\n&nbsp;\r\n\r\nAssume that K = 0.25 and [latex]\\tau[\/latex]is a variable:\r\n\r\n[latex]s^{2} + \\frac{1}{\\tau}s + \\frac{0.25}{\\tau} = 0 [\/latex] [latex]\\rightarrow[\/latex]\u00a0 \u00a0 \u00a0[latex]\\tau s^{2} + s + 0.25 = 0[\/latex]\r\n\r\n&nbsp;\r\n\r\nFind analytical expressions for both poles [latex]p_{1}, p_{2}[\/latex] as a function of [latex]\\tau[\/latex].\r\n\r\n&nbsp;\r\n\r\n<strong>7.3.16 Example<\/strong>\r\n\r\nConsider two closed loop systems as shown in the first block diagram:\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_17-300x104.png\" alt=\"\" width=\"534\" height=\"185\" class=\"wp-image-832 aligncenter\" \/><\/p>\r\n&nbsp;\r\n\r\nThe process transfer function [latex]G_{p}(s)[\/latex] is given by:\r\n\r\n[latex]G_{p}(s) = \\frac{1}{s+p}[\/latex]\r\n\r\nShow that the closed loop system of the first system is of a second order. Find the range of gains for closed loop stability, the critical gain and the frequency of resulting marginally stable oscillations. Next, reconfigure the controller as shown in the second block diagram and show that both closed loop systems have the same characteristic equation.\r\n\r\n&nbsp;\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_18-300x97.png\" alt=\"\" width=\"516\" height=\"167\" class=\"wp-image-833 aligncenter\" \/><\/p>\r\nSuppose that a choice of K is made so that both of the closed loop systems are stable. The graph shown next illustrates their step responses for this choice of K. Identify which step response corresponds to which configuration. Briefly justify your answer.\r\n\r\n&nbsp;\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_19-300x206.png\" alt=\"\" width=\"470\" height=\"324\" class=\"wp-image-834 aligncenter\" \/><\/p>\r\n&nbsp;\r\n\r\n<strong>7.3.17 Example<\/strong>\r\n\r\nConsider again the system from Example 5.3.9, describing a certain system under Proportional + Rate Feedback Control. Find the closed loop system transfer function in terms of controller gains [latex]K_{p}[\/latex] and [latex]K_{d}[\/latex] and determine values of the controller gains such that PO = 10% and Settling time (within [latex]\\pm2\\%[\/latex]) = 1 second. Write out the closed loop transfer function of the system for these values of the controller gains.\r\n\r\n&nbsp;\r\n\r\n<strong>7.3.18 Example<\/strong>\r\n\r\nConsider a certain process described by the following transfer function:\r\n\r\n&nbsp;\r\n\r\n[latex]G_{op}(s) = \\frac{200}{s^{s} + 5s + 49}[\/latex]\r\n\r\n&nbsp;\r\n\r\nFind the specifications of a closed loop system without any controller. Next, assume Proportional Control and find the controller gain such that the closed loop response has a steady state error no larger than 4%. Finally, add the rate feedback to the controller scheme and find an appropriate Derivative gain such that the Percent Overshoot is no more than 15%. Estimate what the resulting settling time would then be.\r\n\r\n&nbsp;\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_20-300x158.png\" alt=\"\" width=\"403\" height=\"212\" class=\" wp-image-836 aligncenter\" \/><\/p>\r\n&nbsp;\r\n\r\n<strong>7.3.19 Example<\/strong>\r\n\r\nLet's continue with the previous example. Assume that we have the same process transfer function that the closed loop system will have the Rate Feedback, as well as Proportional Controller scheme. We would like to have the Percent Overshoot equal to 15%, and the settling time (2% criterion) equal to 0.1 seconds. Find appropriate values for both Controller gains, and estimate the resulting steady state error.\r\n\r\n&nbsp;\r\n\r\n<strong>7.3.20 Example<\/strong>\r\n\r\nConsider the block diagram below, describing a certain control system where a Proportional + Rate Feedback control is implemented with two gains [latex]K_{p}[\/latex] and [latex]K_{d}[\/latex] .\r\n\r\n&nbsp;\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_21-300x147.png\" alt=\"\" width=\"398\" height=\"196\" class=\"wp-image-837 aligncenter\" \/><\/p>\r\n&nbsp;\r\n\r\nFind a closed loop system transfer function in terms of controller gains, [latex]K_{p}[\/latex] and [latex]K_{d}[\/latex]. Next, find the values of gains [latex]K_{p}[\/latex] and [latex]K_{d}[\/latex]. such that the resulting Percent Overshoot of the closed loop step response will be equal to 15% and the settling time, [latex]T_{settle\\pm2\\%}[\/latex], will be equal to 1.5 seconds. What is the closed loop transfer function expression for the computed values of controller gains? For the computed values of controller gains, find the closed loop system DC gain [latex]K_{dc}[\/latex], and the closed loop steady state error for the step response, [latex]e_{ss(step)\\%}[\/latex].\r\n\r\n&nbsp;\r\n\r\n<strong>7.3.21 Example<\/strong>\r\n\r\nConsider the block diagram below, describing a control system where the Proportional + Rate Feedback control is implemented with two control parameters, K and [latex]T_{d}[\/latex] and an inner feedback loop. Note that traditionally, to denote a Rate (as well as a Derivative) Gain, two names are interchangeably used - Rate (or Derivative) Gain, and Rate (or Derivative) Time Constant, which is the inverse of the Gain. Note as well that this is a slightly different P + Rate Feedback arrangement of components than the one in Example 7.3.20 (i.e. the inner feedback loop).\r\n\r\n&nbsp;\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_22-300x173.png\" alt=\"\" width=\"443\" height=\"255\" class=\"wp-image-838 aligncenter\" \/><\/p>\r\n&nbsp;\r\n\r\nFirst, find both closed loop system transfer functions in terms of controller parameters [latex]K, T_{d}[\/latex]. Next, assume the Disturbance signal to be zero and find their values such that the steady state error of the system step response, [latex]e_{ss(step)\\%}[\/latex], is equal to 10%, and the closed loop damping ratio [latex]\\zeta[\/latex]equal to 0.7. For the calculated values of controller parameters, estimate the resulting settling time of the step response, [latex]T_{settle\\pm 2\\%}[\/latex].\r\n\r\n&nbsp;\r\n\r\nNext, assume that [latex]r(t) = 1(t)[\/latex] and [latex]d(t) = 0.5 \\cdot 1(t)[\/latex] where 1(t) is a unit step function. If K and [latex]T_{d}[\/latex] are as calculated above, what is the steady state value of the output signal? What will the steady state error be? Repeat for [latex]r(t) = 1(t)[\/latex] and [latex]d(t) = 10 \\cdot 1(t)[\/latex] What needs to be done to reduce the effect of the disturbance on the system response? Explain briefly.\r\n\r\n&nbsp;\r\n\r\n<strong>7.3.22 Example<\/strong>\r\n\r\nA feedback control system with positive controller gains [latex]K_{1}[\/latex] and [latex]K_{2}[\/latex] is configured as follows:\r\n\r\n&nbsp;\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_23-300x140.png\" alt=\"\" width=\"505\" height=\"236\" class=\"wp-image-839 aligncenter\" \/><\/p>\r\nFind an expression for [latex]K_{2}[\/latex] in terms of [latex]K_{1}[\/latex] in terms of so that the steady state error to a ramp ( [latex]r(t) = t, t \\geq 0[\/latex] ), is less than 1 unit. Sketch the desired locations of the closed loop system poles in the complex plane in order to achieve the following performance specifications:\r\n<ul>\r\n \t<li>The damping ratio of the poles [latex]\\zeta \\geq 0.707[\/latex]<\/li>\r\n \t<li>The settling time [latex]T_{settle \\pm2\\%} \\geq 3[\/latex] seconds.<\/li>\r\n<\/ul>\r\nSet the rate feedback gain [latex]K_{2} = 0.1[\/latex] and find the minimum value of the proportional gain [latex]K_{1}[\/latex] so that all of the performance specifications listed in Parts 1 and 2 can be achieved.\r\n\r\n&nbsp;\r\n\r\n<strong>7.3.23 Example<\/strong>\r\n\r\nConsider a closed loop position control system working under Proportional + Rate Feedback Control, as shown.\r\n\r\n&nbsp;\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_24-300x135.png\" alt=\"\" width=\"504\" height=\"227\" class=\"wp-image-840 aligncenter\" \/><\/p>\r\n&nbsp;\r\n\r\nDetermine the Proportional Gain value [latex]K_{p}[\/latex] such that the following performance specifications can be achieved: the damping ratio of the poles [latex]\\zeta \\geq 0.707[\/latex] and the settling time [latex]T_{settle \\pm2\\%} \\geq 3[\/latex] seconds. For the value of as found above, estimate the following closed loop specifications: [latex]PO, T_{rise(10\\% - 90\\%)}, T_{settle \\pm2\\%} , T_{period}[\/latex] . Also, determine the System Type, Error Constants and Steady State Errors.\r\n\r\n&nbsp;\r\n\r\nPart 3. If the Proportional + Rate Feedback Control is replaced by the Proportional + Derivative Control, how would the response specifications under P + D Control change, compared to your calculations in Part 2 for Proportional + Rate Feedback?\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_25-300x124.png\" alt=\"\" width=\"508\" height=\"210\" class=\"wp-image-841 aligncenter\" \/><\/p>\r\n&nbsp;\r\n\r\n<strong>7.3.24 Example<\/strong>\r\n\r\nConsider a closed loop control system working under a Proportional + Rate Feedback Control, as shown below:\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_26-300x168.png\" alt=\"\" width=\"436\" height=\"244\" class=\"wp-image-842 aligncenter\" \/><\/p>\r\nFind the controller gains [latex]K_{p}, K_{d}[\/latex]such that the closed loop system will meet the following conditions:\r\n<ul>\r\n \t<li>The closed loop operation is stable;<\/li>\r\n \t<li>The steady state error, in %, for a normalized step input, is equal to 5%;<\/li>\r\n \t<li>The closed loop step response has PO = 5%.<\/li>\r\n<\/ul>\r\nWith the controller gain values as calculated, what will be the step response Settling Time (within 2%)?\r\n\r\n&nbsp;\r\n\r\n<strong>7.3.25 Example<\/strong>\r\n\r\nConsider the same block diagram, shown below, as in Example 2.6.11, of the servo-control system for a position control of one of the joints of a robot arm, operating under Proportional Control. Let\u2019s assume a <strong>simplified<\/strong> model for this system, shown below, where the armature inductance L = 0 H. All other parameters remain the same as in Example 2.6.11.\r\n\r\n&nbsp;\r\n<p style=\"text-align: center\"><img src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_27-300x127.png\" alt=\"\" width=\"550\" height=\"233\" class=\"wp-image-844 aligncenter\" \/><\/p>\r\n&nbsp;\r\n\r\nFind the closed loop transfer function between reference [latex]\\omega_{ref}[\/latex] angle and the load position angle [latex]\\omega_{load}[\/latex] for the simplified model of the system:\r\n\r\n&nbsp;\r\n\r\n[latex]G_{m}(s) = \\frac{\\omega_{load}(s)}{\\omega_{ref}(s)}[\/latex]\r\n\r\n&nbsp;\r\n\r\nNext, find the value of the controller gain such that the closed loop system has the damping ratio [latex]\\zeta \\geq 0.707[\/latex] of. For this value of the controller gain, estimate Percent Overshoot, PO, of the system unit step response, Steady State Error [latex]e_{ss(step)\\%}[\/latex], and Settling Time, [latex]T_{settle\\pm 2\\%}[\/latex].","rendered":"<p><strong>7.3.1 Example<\/strong><\/p>\n<p>Consider a certain closed loop control system as shown:<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_5-300x123.png\" alt=\"\" width=\"300\" height=\"123\" class=\"aligncenter size-medium wp-image-815 aligncenter\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_5-300x123.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_5-65x27.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_5-225x93.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_5-350x144.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_5.png 447w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>Find the closed loop system transfer function and determine the system parameters [latex]K_{dc}, \\zeta,\\omega_{o}[\/latex]. Next, determine the following step response specifications: Percent Overshoot (PO), Settling Time ([latex]T_{settle(\\pm 2\\%)}[\/latex]), Rise Time ([latex]T_{rise(10\\% - 90\\%)}[\/latex]), period of oscillations ([latex]T_{period}[\/latex]), and frequency of damped oscillations ([latex]\\omega_{d}[\/latex]), the System Type, Error Constants and Steady State Errors for the step, ramp and parabolic inputs.<\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.2 Example<\/strong><\/p>\n<p>Consider a certain closed loop system operating under Proportional Control as shown, and find the gain value such that the system is stable and PO is approximately 20%. What is the Settling Time? Can it be improved?<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_6-300x80.png\" alt=\"\" width=\"506\" height=\"135\" class=\"wp-image-817 aligncenter\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_6-300x80.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_6-65x17.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_6-225x60.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_6-350x93.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_6.png 548w\" sizes=\"auto, (max-width: 506px) 100vw, 506px\" \/><\/p>\n<p><strong>7.3.3 Example<\/strong><\/p>\n<p>Consider a pole-zero map of a certain closed loop system, as shown. Estimate the settling time, [latex]T_{settle(2\\%)}[\/latex], of the system step response and the closed loop system damping ratio.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_7-300x232.png\" alt=\"\" width=\"472\" height=\"365\" class=\"wp-image-818 aligncenter\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_7-300x232.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_7-65x50.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_7-225x174.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_7-350x270.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_7.png 470w\" sizes=\"auto, (max-width: 472px) 100vw, 472px\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.4 Example<\/strong><\/p>\n<p>Consider an unknown closed loop system with a normalized (i.e. scaled so that the reference input is equal to ) step response as shown. Find an appropriate model for the closed loop transfer function.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_8-300x225.png\" alt=\"\" width=\"547\" height=\"410\" class=\"wp-image-819 aligncenter\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_8-300x225.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_8-768x576.png 768w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_8-65x49.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_8-225x169.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_8-350x263.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_8.png 826w\" sizes=\"auto, (max-width: 547px) 100vw, 547px\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.5 Example<\/strong><\/p>\n<p>Consider a response of a closed loop control system from Example 5.3.10. Read off transient and steady state step response specifications ([latex]PO, T_{rise(10\\% - 90\\%)} , T_{settle \\pm 2\\%}, T_{period},[\/latex] and [latex]e_{ss\\%}[\/latex]). Based on the information, build an appropriate second order model for the system with such step response as shown.<\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.6 Example<\/strong><\/p>\n<p>Consider a certain closed loop control system described by the following transfer function:<\/p>\n<p>[latex]G_{cl}(s) = \\frac{Y(s)}{R(s)} = \\frac{22.5}{s^{2} + s + 25}[\/latex]<\/p>\n<p>Find the closed loop system damping ratio, frequency of natural oscillation and closed loop DC gain.<\/p>\n<p>Next, estimate the following transient response specifications: percent overshoot (PO), settling time ([latex]T_{settle(\\pm 2\\%)}[\/latex]), period ( [latex]T_{period}[\/latex]), and frequency of damped oscillations (), as well as the following steady state specifications of this closed loop system: System Type as well as Position Constant, steady state error to a step input (in %), Velocity Constant, steady state error to a ramp input, Acceleration Constant and steady state error to a parabolic input.<\/p>\n<p>How many cycles of oscillations will be visible in the system response? Justify your answer.<\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.7 Example<\/strong><\/p>\n<p>Consider a response of a certain closed loop control system to a unit reference signal, shown in the figure below.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_9-300x240.png\" alt=\"\" width=\"530\" height=\"424\" class=\"wp-image-821 aligncenter\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_9-300x240.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_9-768x615.png 768w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_9-65x52.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_9-225x180.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_9-350x280.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_9.png 881w\" sizes=\"auto, (max-width: 530px) 100vw, 530px\" \/><\/p>\n<p>&nbsp;<\/p>\n<p>Read off appropriate values and\/or calculate transient specifications (PO, settling time ([latex]T_{settle(\\pm 2\\%)}[\/latex]), period ( [latex]T_{period}[\/latex]) for this step response. Identify the System Type, Steady State Errors to unit step, ramp and parabolic inputs, as well as the corresponding Position, Velocity and Acceleration Constants. Based on the information read off in Part 1, create a second order model for the closed loop system with the response shown. Find the following system parameters: [latex]\\zeta, \\omega_{n}, K_{dc}[\/latex] , as well as the complete model transfer function [latex]G_{model}(s)[\/latex] .<\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.8 Example<\/strong><\/p>\n<p>Consider a certain closed loop control system described by the following transfer function:<\/p>\n<p>[latex]G_{cl}(s) = \\frac{Y(s)}{R(s)} = \\frac{80}{s^{2} + 5s + 100}[\/latex]<\/p>\n<p>Find the following model parameters: [latex]\\zeta, \\omega_{n}, K_{dc}[\/latex]. Estimate transient response specifications (PO, settling time ([latex]T_{settle(\\pm 2\\%)}[\/latex]), period ( [latex]T_{period}[\/latex]) and steady state specifications of this closed loop system (System Type, [latex]K_{pos}, e_{ss(step)\\%}, K_{v}, e_{ss(ramp)}, K_{a}, e_{ss(parab)}[\/latex] ).<\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.9 Example<\/strong><\/p>\n<p>Consider four separate second order systems, with the locations of their pole pairs shown. Answer the following questions and give brief justification to your answer.<\/p>\n<p><strong>Q:<\/strong> Which of the four systems exhibits the largest percent overshoot (PO) in its step response?<\/p>\n<p><strong>Q:<\/strong> Which of the four systems is unstable?<\/p>\n<p><strong>Q:<\/strong> Which of the four systems exhibits the shortest settling time in its step response?<\/p>\n<p><strong>Q:<\/strong> Which of the four systems has the highest frequency of oscillations in its step response?<\/p>\n<p><strong>Q:<\/strong> Which of the four systems exhibits the longest settling time in its step response?<\/p>\n<p><strong>Q:<\/strong> Which of the four systems exhibits the smallest percent overshoot (PO) in its step response?<\/p>\n<p><strong>Q:<\/strong> Which of the four systems has the smallest steady state error?<\/p>\n<p><strong>Q:<\/strong> What is the System Type?<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_10-300x239.png\" alt=\"\" width=\"527\" height=\"421\" class=\"wp-image-822 aligncenter\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_10-300x239.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_10-768x612.png 768w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_10-65x52.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_10-225x179.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_10-350x279.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_10.png 796w\" sizes=\"auto, (max-width: 527px) 100vw, 527px\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.10 Example<\/strong><\/p>\n<p>Consider closed loop responses of two different control systems (System A and System B), as shown. Match them to their appropriate pole locations also shown, briefly explain why.<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_11-300x243.png\" alt=\"\" width=\"432\" height=\"350\" class=\"alignnone wp-image-823\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_11-300x243.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_11-65x53.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_11-225x182.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_11-350x284.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_11.png 506w\" sizes=\"auto, (max-width: 432px) 100vw, 432px\" \/><\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_12-300x217.png\" alt=\"\" width=\"487\" height=\"352\" class=\"alignnone wp-image-824\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_12-300x217.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_12-65x47.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_12-225x163.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_12-350x253.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_12.png 513w\" sizes=\"auto, (max-width: 487px) 100vw, 487px\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.11 Example<\/strong><\/p>\n<p>Consider a normalized step response of a certain LTI system, as shown. The reference is assumed to be a unit step.<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_13-300x225.png\" alt=\"\" width=\"605\" height=\"455\" class=\"wp-image-826 aligncenter\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_13-300x225.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_13-768x576.png 768w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_13-65x49.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_13-225x169.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_13-350x262.png 350w\" sizes=\"auto, (max-width: 605px) 100vw, 605px\" \/><\/p>\n<p>Determine the Percent Overshoot (in %), Steady State Error (in %) and the Settling Time (within \u00b12% of the final value) for this response. Next, assume that this system can be modelled by a standard 2nd order model and calculate the appropriate parameters.<\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.12 Example<\/strong><\/p>\n<p>Consider a response of a certain closed loop control system to a unit reference signal, shown in the figure below.<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_14-300x257.png\" alt=\"\" width=\"594\" height=\"509\" class=\"wp-image-827 aligncenter\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_14-300x257.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_14-768x658.png 768w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_14-65x56.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_14-225x193.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_14-350x300.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_14.png 961w\" sizes=\"auto, (max-width: 594px) 100vw, 594px\" \/><\/p>\n<p>Read off appropriate values and\/or calculate transient specifications (PO, settling time ([latex]T_{settle(\\pm 2\\%)}[\/latex]), period ([latex]T_{period}[\/latex]) for this step response. Based on the information read off in Part 1, create a second order model for the closed loop system with the response shown. Find the following system parameters: [latex]\\zeta, \\omega_{n}, K_{dc}[\/latex], as well as the complete model transfer function [latex]G_{model}(s)[\/latex]. Identify the System Type, Steady State Errors to unit step, ramp and parabolic inputs, as well as the corresponding Position, Velocity and Acceleration Constants.<\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.13 Example<\/strong><\/p>\n<p>Consider a step response to a unit reference input of a control system as shown. Estimate the following specs: Percent Overshoot, Settling Time the Steady State Error. What are your estimates of the closed loop damping ratio [latex]\\zeta[\/latex], the frequency of natural oscillations [latex]\\omega_{n}[\/latex], and the DC gain?<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_15-300x220.png\" alt=\"\" width=\"588\" height=\"431\" class=\"wp-image-828 aligncenter\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_15-300x220.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_15-768x563.png 768w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_15-65x48.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_15-225x165.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_15-350x257.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_15.png 995w\" sizes=\"auto, (max-width: 588px) 100vw, 588px\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.14 Example<\/strong><\/p>\n<p>A step response of a certain control system is supposed to exhibit no more than 5% overshoot and to settle (use the 2% definition of the settling time) within (2) seconds. Show a shaded area in the S-Plane where the dominant closed loop poles of the system should be located so that both conditions are met.<\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.15 Example<\/strong><\/p>\n<p>Consider the closed loop control system as shown here.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_16-300x102.png\" alt=\"\" width=\"460\" height=\"156\" class=\"wp-image-829 aligncenter\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_16-300x102.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_16-65x22.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_16-225x76.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_16-350x119.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_16.png 635w\" sizes=\"auto, (max-width: 460px) 100vw, 460px\" \/><\/p>\n<p>For [latex]\\tau = = 2[\/latex] seconds, the desired closed loop ratio is to be [latex]\\zeta = \\frac{1}{\\sqrt{2}}[\/latex]. Find the corresponding Controller gain K and the resulting settling time of the closed loop step response. Next, assume that the desired closed loop ratio is still to be [latex]\\zeta = \\frac{1}{\\sqrt{2}}[\/latex]. but we would like to shorten the settling time to [latex]T_{settle \\pm 2\\%} =\u00a0 2[\/latex] seconds. If the time constant is variable, what value would it have to be? For that case, find the corresponding Controller gain K.<\/p>\n<p>The closed loop system characteristic equation Q(s) is a quadratic, resulting in TWO closed loop poles:<\/p>\n<p>&nbsp;<\/p>\n<p>[latex]Q(s) = 0[\/latex]\u00a0 \u00a0 \u00a0[latex]s^{2} + \\frac{1}{\\tau}s + \\frac{K}{\\tau} = 0[\/latex]<\/p>\n<p>&nbsp;<\/p>\n<p>Assume that K = 0.25 and [latex]\\tau[\/latex]is a variable:<\/p>\n<p>[latex]s^{2} + \\frac{1}{\\tau}s + \\frac{0.25}{\\tau} = 0[\/latex] [latex]\\rightarrow[\/latex]\u00a0 \u00a0 \u00a0[latex]\\tau s^{2} + s + 0.25 = 0[\/latex]<\/p>\n<p>&nbsp;<\/p>\n<p>Find analytical expressions for both poles [latex]p_{1}, p_{2}[\/latex] as a function of [latex]\\tau[\/latex].<\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.16 Example<\/strong><\/p>\n<p>Consider two closed loop systems as shown in the first block diagram:<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_17-300x104.png\" alt=\"\" width=\"534\" height=\"185\" class=\"wp-image-832 aligncenter\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_17-300x104.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_17-65x22.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_17-225x78.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_17-350x121.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_17.png 741w\" sizes=\"auto, (max-width: 534px) 100vw, 534px\" \/><\/p>\n<p>&nbsp;<\/p>\n<p>The process transfer function [latex]G_{p}(s)[\/latex] is given by:<\/p>\n<p>[latex]G_{p}(s) = \\frac{1}{s+p}[\/latex]<\/p>\n<p>Show that the closed loop system of the first system is of a second order. Find the range of gains for closed loop stability, the critical gain and the frequency of resulting marginally stable oscillations. Next, reconfigure the controller as shown in the second block diagram and show that both closed loop systems have the same characteristic equation.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_18-300x97.png\" alt=\"\" width=\"516\" height=\"167\" class=\"wp-image-833 aligncenter\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_18-300x97.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_18-768x249.png 768w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_18-65x21.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_18-225x73.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_18-350x113.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_18.png 797w\" sizes=\"auto, (max-width: 516px) 100vw, 516px\" \/><\/p>\n<p>Suppose that a choice of K is made so that both of the closed loop systems are stable. The graph shown next illustrates their step responses for this choice of K. Identify which step response corresponds to which configuration. Briefly justify your answer.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_19-300x206.png\" alt=\"\" width=\"470\" height=\"324\" class=\"wp-image-834 aligncenter\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_19-300x206.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_19-768x528.png 768w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_19-65x45.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_19-225x155.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_19-350x241.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_19.png 855w\" sizes=\"auto, (max-width: 470px) 100vw, 470px\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.17 Example<\/strong><\/p>\n<p>Consider again the system from Example 5.3.9, describing a certain system under Proportional + Rate Feedback Control. Find the closed loop system transfer function in terms of controller gains [latex]K_{p}[\/latex] and [latex]K_{d}[\/latex] and determine values of the controller gains such that PO = 10% and Settling time (within [latex]\\pm2\\%[\/latex]) = 1 second. Write out the closed loop transfer function of the system for these values of the controller gains.<\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.18 Example<\/strong><\/p>\n<p>Consider a certain process described by the following transfer function:<\/p>\n<p>&nbsp;<\/p>\n<p>[latex]G_{op}(s) = \\frac{200}{s^{s} + 5s + 49}[\/latex]<\/p>\n<p>&nbsp;<\/p>\n<p>Find the specifications of a closed loop system without any controller. Next, assume Proportional Control and find the controller gain such that the closed loop response has a steady state error no larger than 4%. Finally, add the rate feedback to the controller scheme and find an appropriate Derivative gain such that the Percent Overshoot is no more than 15%. Estimate what the resulting settling time would then be.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_20-300x158.png\" alt=\"\" width=\"403\" height=\"212\" class=\"wp-image-836 aligncenter\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_20-300x158.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_20-65x34.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_20-225x118.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_20-350x184.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_20.png 612w\" sizes=\"auto, (max-width: 403px) 100vw, 403px\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.19 Example<\/strong><\/p>\n<p>Let&#8217;s continue with the previous example. Assume that we have the same process transfer function that the closed loop system will have the Rate Feedback, as well as Proportional Controller scheme. We would like to have the Percent Overshoot equal to 15%, and the settling time (2% criterion) equal to 0.1 seconds. Find appropriate values for both Controller gains, and estimate the resulting steady state error.<\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.20 Example<\/strong><\/p>\n<p>Consider the block diagram below, describing a certain control system where a Proportional + Rate Feedback control is implemented with two gains [latex]K_{p}[\/latex] and [latex]K_{d}[\/latex] .<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_21-300x147.png\" alt=\"\" width=\"398\" height=\"196\" class=\"wp-image-837 aligncenter\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_21-300x147.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_21-65x32.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_21-225x110.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_21-350x171.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_21.png 628w\" sizes=\"auto, (max-width: 398px) 100vw, 398px\" \/><\/p>\n<p>&nbsp;<\/p>\n<p>Find a closed loop system transfer function in terms of controller gains, [latex]K_{p}[\/latex] and [latex]K_{d}[\/latex]. Next, find the values of gains [latex]K_{p}[\/latex] and [latex]K_{d}[\/latex]. such that the resulting Percent Overshoot of the closed loop step response will be equal to 15% and the settling time, [latex]T_{settle\\pm2\\%}[\/latex], will be equal to 1.5 seconds. What is the closed loop transfer function expression for the computed values of controller gains? For the computed values of controller gains, find the closed loop system DC gain [latex]K_{dc}[\/latex], and the closed loop steady state error for the step response, [latex]e_{ss(step)\\%}[\/latex].<\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.21 Example<\/strong><\/p>\n<p>Consider the block diagram below, describing a control system where the Proportional + Rate Feedback control is implemented with two control parameters, K and [latex]T_{d}[\/latex] and an inner feedback loop. Note that traditionally, to denote a Rate (as well as a Derivative) Gain, two names are interchangeably used &#8211; Rate (or Derivative) Gain, and Rate (or Derivative) Time Constant, which is the inverse of the Gain. Note as well that this is a slightly different P + Rate Feedback arrangement of components than the one in Example 7.3.20 (i.e. the inner feedback loop).<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_22-300x173.png\" alt=\"\" width=\"443\" height=\"255\" class=\"wp-image-838 aligncenter\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_22-300x173.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_22-65x37.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_22-225x130.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_22-350x202.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_22.png 660w\" sizes=\"auto, (max-width: 443px) 100vw, 443px\" \/><\/p>\n<p>&nbsp;<\/p>\n<p>First, find both closed loop system transfer functions in terms of controller parameters [latex]K, T_{d}[\/latex]. Next, assume the Disturbance signal to be zero and find their values such that the steady state error of the system step response, [latex]e_{ss(step)\\%}[\/latex], is equal to 10%, and the closed loop damping ratio [latex]\\zeta[\/latex]equal to 0.7. For the calculated values of controller parameters, estimate the resulting settling time of the step response, [latex]T_{settle\\pm 2\\%}[\/latex].<\/p>\n<p>&nbsp;<\/p>\n<p>Next, assume that [latex]r(t) = 1(t)[\/latex] and [latex]d(t) = 0.5 \\cdot 1(t)[\/latex] where 1(t) is a unit step function. If K and [latex]T_{d}[\/latex] are as calculated above, what is the steady state value of the output signal? What will the steady state error be? Repeat for [latex]r(t) = 1(t)[\/latex] and [latex]d(t) = 10 \\cdot 1(t)[\/latex] What needs to be done to reduce the effect of the disturbance on the system response? Explain briefly.<\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.22 Example<\/strong><\/p>\n<p>A feedback control system with positive controller gains [latex]K_{1}[\/latex] and [latex]K_{2}[\/latex] is configured as follows:<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_23-300x140.png\" alt=\"\" width=\"505\" height=\"236\" class=\"wp-image-839 aligncenter\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_23-300x140.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_23-65x30.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_23-225x105.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_23-350x164.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_23.png 732w\" sizes=\"auto, (max-width: 505px) 100vw, 505px\" \/><\/p>\n<p>Find an expression for [latex]K_{2}[\/latex] in terms of [latex]K_{1}[\/latex] in terms of so that the steady state error to a ramp ( [latex]r(t) = t, t \\geq 0[\/latex] ), is less than 1 unit. Sketch the desired locations of the closed loop system poles in the complex plane in order to achieve the following performance specifications:<\/p>\n<ul>\n<li>The damping ratio of the poles [latex]\\zeta \\geq 0.707[\/latex]<\/li>\n<li>The settling time [latex]T_{settle \\pm2\\%} \\geq 3[\/latex] seconds.<\/li>\n<\/ul>\n<p>Set the rate feedback gain [latex]K_{2} = 0.1[\/latex] and find the minimum value of the proportional gain [latex]K_{1}[\/latex] so that all of the performance specifications listed in Parts 1 and 2 can be achieved.<\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.23 Example<\/strong><\/p>\n<p>Consider a closed loop position control system working under Proportional + Rate Feedback Control, as shown.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_24-300x135.png\" alt=\"\" width=\"504\" height=\"227\" class=\"wp-image-840 aligncenter\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_24-300x135.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_24-65x29.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_24-225x101.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_24-350x157.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_24.png 707w\" sizes=\"auto, (max-width: 504px) 100vw, 504px\" \/><\/p>\n<p>&nbsp;<\/p>\n<p>Determine the Proportional Gain value [latex]K_{p}[\/latex] such that the following performance specifications can be achieved: the damping ratio of the poles [latex]\\zeta \\geq 0.707[\/latex] and the settling time [latex]T_{settle \\pm2\\%} \\geq 3[\/latex] seconds. For the value of as found above, estimate the following closed loop specifications: [latex]PO, T_{rise(10\\% - 90\\%)}, T_{settle \\pm2\\%} , T_{period}[\/latex] . Also, determine the System Type, Error Constants and Steady State Errors.<\/p>\n<p>&nbsp;<\/p>\n<p>Part 3. If the Proportional + Rate Feedback Control is replaced by the Proportional + Derivative Control, how would the response specifications under P + D Control change, compared to your calculations in Part 2 for Proportional + Rate Feedback?<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_25-300x124.png\" alt=\"\" width=\"508\" height=\"210\" class=\"wp-image-841 aligncenter\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_25-300x124.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_25-65x27.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_25-225x93.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_25-350x145.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_25.png 670w\" sizes=\"auto, (max-width: 508px) 100vw, 508px\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.24 Example<\/strong><\/p>\n<p>Consider a closed loop control system working under a Proportional + Rate Feedback Control, as shown below:<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_26-300x168.png\" alt=\"\" width=\"436\" height=\"244\" class=\"wp-image-842 aligncenter\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_26-300x168.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_26-65x36.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_26-225x126.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_26-350x195.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_26.png 650w\" sizes=\"auto, (max-width: 436px) 100vw, 436px\" \/><\/p>\n<p>Find the controller gains [latex]K_{p}, K_{d}[\/latex]such that the closed loop system will meet the following conditions:<\/p>\n<ul>\n<li>The closed loop operation is stable;<\/li>\n<li>The steady state error, in %, for a normalized step input, is equal to 5%;<\/li>\n<li>The closed loop step response has PO = 5%.<\/li>\n<\/ul>\n<p>With the controller gain values as calculated, what will be the step response Settling Time (within 2%)?<\/p>\n<p>&nbsp;<\/p>\n<p><strong>7.3.25 Example<\/strong><\/p>\n<p>Consider the same block diagram, shown below, as in Example 2.6.11, of the servo-control system for a position control of one of the joints of a robot arm, operating under Proportional Control. Let\u2019s assume a <strong>simplified<\/strong> model for this system, shown below, where the armature inductance L = 0 H. All other parameters remain the same as in Example 2.6.11.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/pressbooks.library.ryerson.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_27-300x127.png\" alt=\"\" width=\"550\" height=\"233\" class=\"wp-image-844 aligncenter\" srcset=\"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_27-300x127.png 300w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_27-768x325.png 768w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_27-65x28.png 65w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_27-225x95.png 225w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_27-350x148.png 350w, https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-content\/uploads\/sites\/75\/2019\/08\/fig7_27.png 803w\" sizes=\"auto, (max-width: 550px) 100vw, 550px\" \/><\/p>\n<p>&nbsp;<\/p>\n<p>Find the closed loop transfer function between reference [latex]\\omega_{ref}[\/latex] angle and the load position angle [latex]\\omega_{load}[\/latex] for the simplified model of the system:<\/p>\n<p>&nbsp;<\/p>\n<p>[latex]G_{m}(s) = \\frac{\\omega_{load}(s)}{\\omega_{ref}(s)}[\/latex]<\/p>\n<p>&nbsp;<\/p>\n<p>Next, find the value of the controller gain such that the closed loop system has the damping ratio [latex]\\zeta \\geq 0.707[\/latex] of. For this value of the controller gain, estimate Percent Overshoot, PO, of the system unit step response, Steady State Error [latex]e_{ss(step)\\%}[\/latex], and Settling Time, [latex]T_{settle\\pm 2\\%}[\/latex].<\/p>\n","protected":false},"author":118,"menu_order":3,"template":"","meta":{"pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-812","chapter","type-chapter","status-publish","hentry"],"part":758,"_links":{"self":[{"href":"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-json\/pressbooks\/v2\/chapters\/812","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-json\/wp\/v2\/users\/118"}],"version-history":[{"count":28,"href":"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-json\/pressbooks\/v2\/chapters\/812\/revisions"}],"predecessor-version":[{"id":2659,"href":"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-json\/pressbooks\/v2\/chapters\/812\/revisions\/2659"}],"part":[{"href":"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-json\/pressbooks\/v2\/parts\/758"}],"metadata":[{"href":"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-json\/pressbooks\/v2\/chapters\/812\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-json\/wp\/v2\/media?parent=812"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-json\/pressbooks\/v2\/chapter-type?post=812"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-json\/wp\/v2\/contributor?post=812"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/pressbooks.library.torontomu.ca\/controlsystems\/wp-json\/wp\/v2\/license?post=812"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}